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	<title>Comments on: 马尔可夫链，概念及应用</title>
	<atom:link href="http://www.sinrain.cn/2008/12/24/markov-chain-concepts-and-applications/feed/" rel="self" type="application/rss+xml" />
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	<description>Simple Dream Easy Go~</description>
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	<item>
		<title>By: SinRain</title>
		<link>http://www.sinrain.cn/2008/12/24/markov-chain-concepts-and-applications/comment-page-1/#comment-587</link>
		<dc:creator>SinRain</dc:creator>
		<pubDate>Thu, 01 Jan 2009 15:23:47 +0000</pubDate>
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		<description>@LYdialu


其中Y是一组列向量，且Yn=0;
Y=P&#039;(Y+1),其中P&#039;为将原单步转移矩阵的第n行替换为(0,0,0,...0) (亦即终点态)

这个题目就是说 Y5 恒等于0，好比电势等于0的点，好比接地了。。</description>
		<content:encoded><![CDATA[<p>@LYdialu</p>
<p>其中Y是一组列向量，且Yn=0;<br />
Y=P'(Y+1),其中P'为将原单步转移矩阵的第n行替换为(0,0,0,...0) (亦即终点态)</p>
<p>这个题目就是说 Y5 恒等于0，好比电势等于0的点，好比接地了。。</p>
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	<item>
		<title>By: LYdialu</title>
		<link>http://www.sinrain.cn/2008/12/24/markov-chain-concepts-and-applications/comment-page-1/#comment-586</link>
		<dc:creator>LYdialu</dc:creator>
		<pubDate>Thu, 01 Jan 2009 12:23:41 +0000</pubDate>
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		<description>&#124; 0 0.5 0 0.5 &#124; &#124;Y3+1&#124;  &#124;Y3&#124;
&#124; 0.5 0 0.5 0 &#124; &#124;Y4+1&#124;= &#124;Y4&#124;
&#124; 0   0 0   0  &#124; &#124;Y5+1&#124;  &#124;Y5&#124;
&#124; 0 0.5 0 0.5 &#124; &#124;Y6+1&#124;  &#124;Y6&#124; ,这步是？我只是自己看过一点点马尔科夫链。。。所以困惑中。。。。</description>
		<content:encoded><![CDATA[<p>| 0 0.5 0 0.5 | |Y3+1|  |Y3|<br />
| 0.5 0 0.5 0 | |Y4+1|= |Y4|<br />
| 0   0 0   0  | |Y5+1|  |Y5|<br />
| 0 0.5 0 0.5 | |Y6+1|  |Y6| ,这步是？我只是自己看过一点点马尔科夫链。。。所以困惑中。。。。</p>
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